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sumit

· started a discussion

· 1 Months ago

this question not exaplion eassy away (Question:153065.0)

all typeing in solution alternete

Question:
A candidate who scores 30% fails by 5 marks, while another candidate who scores 40% marks gets 10 more than minimum pass marks. The minimum marks required to pass are—
Options:
A) 50
B) 70
C) 100
D) 150
Solution:

Let x = total marks


A candidate who scores 30% fails by 5 marks

first candidate score = \(\cfrac{3x}{10}\)

it means minimum passing marks = \(\cfrac{3x}{100}\) + 5 = \(\cfrac{3x}{10}\) + 5


candidate who scores 40% marks gets 10 more than minimum pass marks


it means,


\(\cfrac{40x}{100}\)= 10 + \(\cfrac{3x}{10}\) + 5

\(\cfrac{2x}{5}-\cfrac{3x}{10}\)= 15

\(\cfrac{(4x-3x) }{10} \)= 15

x = 150

minimum passing marks =\(\cfrac{3x}{10}\) + 5 = \(\cfrac{(3\times150)}{10} \) + 5 =\(\cfrac{450}{10}\) + 5 = 45 + 5 = 50

Alternate sol.:

passing marks = passing marks 

          30%+5 = 40%-10

             10% =  15

                1% = 1.5

\(\therefore\) 30% = 45 marks 

 passing marks = 45+5 = 50 marks

 

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct.Kindly go through the solution once again.


Regards
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