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Sonu

· started a discussion

· 1 Months ago

how did we come from 5th line to 6th

Question:

    Minimum value of  1+2tan2θ+3cos2θ    is.

 

Options:
A)

  3+26   

B)

 3

C)

  26-1   

D)

  3+6   

Solution:

  1+2tan2θ+3cos2θ   

  1+2sec2θ-1+3cos2θ   

  =1+2sec2θ-2+3cos2θ   

  =2sec2θ+3cos2θ-1   

  =3cos2θ+2sec2θ-1   

  =3cosθ-2secθ+26-1   

    So minimum value is  26-1   

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