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Sunil mahawar

· started a discussion

· 1 Months ago

solution is not clear (Question:162924.0)

fail

Question:
If the value of tan (60 + x) = 2 + \(\sqrt{3}\), then find the value of tan x.
Options:
A) 2 + \(\sqrt{3}\)
B) 2 - \(\sqrt{3}\) 
C) \(\sqrt{3}+1\)
D) \(\sqrt{3}-1\)
Solution:

Ans: (b) tan(a + b) = \(\cfrac{tan \ a + tan\ b}{1 – tan \ a.tan\ b}\) 

tan(60+x) = \(\cfrac{[tan\ 60° + tan\ x]}{[1 – tan 60° tan x ]}\)

2 + \(\sqrt{3}\) = \(\cfrac{\sqrt{3} + tan\ x }{1 - \sqrt{3} \ tan\ x}\)

2 + \(\sqrt{3}\) - 2\(\sqrt{3}\) tan x – 3 tan x = \(\sqrt{3}\) + tan x

tan x = \(\cfrac{1}{( 2 + \sqrt{3}) }\) = 2 - \(\sqrt{3}\)     

Knowledge Expert

· commented

· 1 Months ago

Dear student,
The given answer and answer solution is correct. Please re-check .

Regards
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