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Knowledge Expert
· commented
· 1 Months ago
Please refer below solution,
As we know , cosX + cosY = 2cos[ (X + Y) / 2 ] cos[ (X - Y) / 2 ]
sinX + sinY = 2sin[ (X + Y) / 2 ] cos[ (X - Y) / 2 ]
Therefore using it , 2sin[ (X + Y) / 2 ] cos[ (X - Y) / 2 ] = a -------1 )
2cos[ (X + Y) / 2 ] cos[ (X - Y) / 2 ] = b -------2)
Divide eqn 1) by eqn 2) , we get
2sin (X + Y) / 2cos(X + Y) = a/b
Therefore, Tan (X + Y) = a/b
Hope you understood
Team TR