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Preeti Sehrawat

· started a discussion

· 1 Months ago

answer is not fully solved (Question:959691.0)

question 51 answer is not given properly

Question:

In the given figure AB is the diameter of bigger circle, ABCD is isosceles trapezium then find the radius of smaller circle in given figure (in cm)

    

Options:
A)

  62+3   

B)

  34–3   

C)

  62–3    

D)

  34+3   

Solution:

    

    AC = BD =  122–62=63   

  ∆   MDC is an equilateral triangle 

    So CD = 6 cm

  ANB≃DNCSOANAC=ABDC=12   

  ∵AC=63   

  

    So  AN=43    &  CN=23   

    

     =  23   

 

    In radius of triangle ANC =  r=areasemi perimeter   

     =  12×12×231283+12   

     =  12–63   

     =  62–3   

Knowledge Expert

· commented

· 1 Months ago

Dear student,
We have done the required changes. kindly re-check

Regards
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