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Shivam kumar

· started a discussion

· 1 Months ago

solution is not satisfactory (Question:84730.0)

question is saying that leak pipe drains out one third of filled water i.e., one third of one third id leaked out and not one third of whole

Question:
Pipe A and Pipe B can fill a tank in 12 hours and 15 hours respectively while Pipe C can empty the full tank in 18 hours. If pipe A is opened at 7 am, Pipe B opened at 8:30 am and Pipe C at 10 am, then after 10 am, how much more time will be taken by all three pipes together to fill the tank?
Options:
A) 5\(\frac{12}{17}\) hours.
B) 6 hours.
C) 6\(\frac{12}{17}\) hours.
D) 7\(\frac{12}{17}\) hours.
Solution:

Let the tank's capacity be 180 lit (LCM of 12, 15, and 18).

A fills 180/12= 15 liter/hour

B fills 180/15=12 liter/hour

C empties 180/8=10 liter/hour

Till 10 am 15x3 + 12x1.5 =45+ 18 = 63 liters

Remaining volume to be filled: 180-63 = 117 liters

After 10 am, when all pipes are opened. 15+12-10=17

liters/hr is filled.

Required time= 117/17 =6 \(\frac{15}{17}\) hour

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