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Amit Shah

· started a discussion

· 1 Months ago

Good one

Question:
139 persons have signed up for an elimination tournament. All players are to be paired up for the first round, but because 139 is an odd number one player gets a bye, which promotes him to the second round, without actually playing in the first round. The pairing continues on the next round, with a bye to any player left over. If the schedule is planned so that a minimum number of matches is required to determine the champion, the number of matches which must be played is
Options:
A) 136
B) 137
C) 138
D) 139
Solution:
Ans: (c) There are 139 players in all. We want to determine 1 champion among them. So all except the Champion should lose. A player can lose only once and since each match produces only one loser, to produce 138 losers, there should be 138 matches that should be played.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
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