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Ravi Raj Meena

· started a discussion

· 1 Months ago

SUM OF THE DIGITS= (SUM OF REMINDERS) / [11-(SUM OF THE QUOTIENT)]
X+Y= (3+9) / [ 11 - (6+4) ]

Question:

If a certain number of two digits is divided by the sum of its digits, then the quotient is 6 and the remainder is 3. If the digits are reversed and the resulting number is divided by the sum of the digits, the quotient is 4 and the remainder is 9. The sum of the digits  of the number is:

Options:
A) 4
B) 6
C) 9
D) 12
Solution:
Ans: (d)

Let the number be 10x + y.

A.T.Q.,

10x + y = (x + y) 6 + 3

4x – 5y = 3                         ..........(i)

A.T.Q.,

10y + x = (x + y) × 4 + 9

6y – 3x = 9                          ..........(ii)

On solving equ. (i) & (ii), we get :

x = 7 & y = 5  \(\Rightarrow\) x + y = 12

Vaibhav Yadav

· commented

· 1 Months ago

is this really a trick ... you just added both sides and formed that stuff . ( YES it is applicable for all such questions..its basic)

Ashwini M

· commented

· 1 Months ago

can it be applied for very qstn of this type?

kush

· commented

· 1 Months ago

how ?
\

ankit kumar

· commented

· 1 Months ago

Yet to be approved!

Sangeeta Vaidya

· commented

· 1 Months ago

11 fix h kya?

Pankaj Mishra

· commented

· 1 Months ago

wao .

TABISH

· commented

· 1 Months ago

nice trick

Siddharth

· commented

· 1 Months ago

thanks

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