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Dephinit Defa

· started a discussion

· 1 Months ago

wrong solution (Question: 339040.0 )

wrong

Question:

The HCF of two numbers is 98 and their LCM is 2352. The sum of the numbers may be —

Options:
A)

1428

B)

1537

C)

1372

D)

1296

Solution:

Ans: (c)

Let the two numbers 98a and 98b

Then, their sum = 98a + 98b = 98(a+b)

⇒Their sum is a multiple of 98. Only option c) is divisible by 98.

Sum of numbers = 1372

Vijay Sharma

· commented

· 1 Months ago

solution is wrong because being only the multiple of 98 cannot sayify other conditions

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
The given solution is correct.
If HCF of two no a and b is X then sum of numbers is Xa +Xb
Therefore in this case Sum is 98a+98b , it means sum will be divisible by 98.
From options only C is correct.

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