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prahlad choudhary

· started a discussion

· 1 Months ago

wrong solution (Question: 293508.0 )

is 2^36+2^31=2^31(2^5-1)right

Question:

If x2 + y2 + 4x + 4y + 8 = 0 and x36 + y31 = n × 2n, find n.

Options:
A)

31

B)

33

C)

35

D)

37

Solution:

Ans: (a)

  

Knowledge Expert

· commented

· 1 Months ago

Dear student,

here we find the value of n
2^31(2^5-1) (2^5= 32)
2^31(32-1)
2^31 (31)
after comparing given expression we get value of n.
given answer is correct.

keep learning keep solving
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