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Mohit Soni

· started a discussion

· 1 Months ago

Wrong solution (Question:246941.0)

Please prove it

Question:
A machine is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The height of the cylindrical part is 3 times the radius. The radius of cylindrical part, hemisphere and conical part is equal and the ratio of height and radii is 4 : 3 in cone. If surface area of the Machine is 2175 cm2, then find the radius.
Options:
A) 8.5 cm.
B) 16 cm 
C) 14 cm 
D) 17 cm
Solution:

Ans: (a)


r2 = \(\cfrac{2175\times3}{29\pi}\)

= \(\cfrac{2175 \times3}{29\times22}\times7\)

= 72

r = 8.5 cm.

Monu Prasad

· commented

· 1 Months ago

sorry surface area of hemisphere

Monu Prasad

· commented

· 1 Months ago

dear Topranker...surface area of slant height is 2pir^2 not 4pir^2.

Knowledge Expert

· commented

· 1 Months ago

Dear Student
The curved surface area of hemisphere =4pir^2/2=2pir^2
The curved surface area of cylinder is =2pirh
The curved surface area of cone=pirl
adding all these surcafe areas
4pir^2+2pirh+pirl=2175cm^2
29pir^2/3=2175
r^2=71.59090
r=8.5cm
Regards
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