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Aviral Vikram

· started a discussion

· 1 Months ago

wrong solution (Question: 232961.0 )

how can the average of 5 numbers be (sum divided by 2).
It has to be (sum divided by 5)

Question:
The average of 5 consecutive integers starting with 'n' is 'm'. What is the average of 6 consecutive integers starting with (n + 2)?
Options:
A) \(\cfrac{2m+5}{2}\)
B) m + 2
C) m + 3
D) \(\cfrac{2m+9}{2}\)
Solution:

Ans: (a)

BHASKAR MUDALA

· commented

· 1 Months ago

average of any no. of consecutive no.s = (first no. + last no.)/2
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