CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Vinay Chakrawarti

· started a discussion

· 1 Months ago

Wrong solution (Question: 111682.0 )

Jo explanation hai it's for parellelogram..not applicable for trapezium..jab 3-4 questions wrong Hai paper me to 195 topper kaise score kr sakta Hai..they are cheaters..

Question:

If M is the mid-point of the side BC of a trapezium ABCD of area X with AB||CD, then consider the following statements:

I. Area of the \(\Delta\)MDA = \(\cfrac{X}{2}\)

II. Area of the \(\Delta\)MCD + area of the \(\Delta\)MBA = \(\cfrac{X}{3}\) 

Options:
A) I alone is correct
B) II alone is correct
C) I and II are correct
D) I and II are false
Solution:
Ans: (a)

Let N be the mid point of the side AD,

Then area of \(\Delta\)MDA


= \(\cfrac{1}{2}\)(Area of trap. ABMN)

+\(\cfrac{1}{2}\)(Area of trap. NMCD)

=  \(\cfrac{1}{2}\)X(area of trap. ABCD)

So, statement I is true.

But statement II cannot be true, other the area of trapezium. ABCD would be less than X.

Abhishek Shah

· commented

· 1 Months ago

Exactly... Topper kon hai ye log...
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions