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Ashok Kumar

· started a discussion

· 1 Months ago

Wrong solution (Question: 107798.0 )

According to ur solution triangle will be isosceles coz u consider the length of perpendicular is equal to it divides the its base so then how can u consider it 3:4:5 ratio

Question:

The semi-perimeter of a right angled triangle ABC is 12 cm and the shortest median is 5 cm. What is area of the triangle which has the largest median of triangle ABC as its longest side?

Options:
A) \(\sqrt[]{73}\) cm2  
B) 10 cm2
C) 12 cm2  
D) None of these
Solution:
Ans: (c) 


Given: S = 12 cm & BP = 5 cm

∴ AP = PC = BP = 5 cm

∴ AC = 10 cm

 We know the ratio of Right triangle like (3:4:5) 

      then we assume the ratio, (6:8:10)

So, the other two sides = 8 cm, 6 cm

∴ Area of ∆QBC = \(\cfrac{1}{2}\times\) QB × BC = \(\cfrac{1}{2}\times\) 4 × 6 = 12 cm2

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct
Please try again

Best wishes
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