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shyam ji Mishra

· started a discussion

· 1 Months ago

it will be 3 , first and second component will become sinsquare cos square and third we know sin max value is 1 so

Question:

     The maximum numerical value of  11+cot2θ+11+tan2θ +2sin2θ    will be: 

Options:
A)

     5 

B)

     6

C)

     3 

D)

     2

Solution:

     Putting θ = 450 in the given equation, we get

11+cot2450  +11+tan2450  +2sin2450   

=11+1+11+1+212    2   

=12+12+1=2   

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