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ANIL KUMAR DESAI

· started a discussion

· 1 Months ago

it will be maximum not minimum

Question:

Minimum shear strain in orthogonal turning with a cutting tool of zero rake angle is

Options:
A)

0.0

B)

0.5

C)

1.0

D)

2.0

  

Solution:

Ans: (d)

 

Knowledge Expert

· commented

· 1 Months ago

Dear Student
∝ = 0°

Shear strain s=cotϕ+tan(ϕ−α)s=cotϕ+tan(ϕ−α)

⇒s=cotϕ+tanϕ⇒s=cotϕ+tanϕ

for minimum value, dsdϕ=0dsdϕ=0

⇒−cosec2ϕ+sec2ϕ=0⇒−1sin2ϕ+1cos2ϕ=0⇒cos2ϕ−sin2ϕ=0⇒cos2ϕ=0⇒ϕ=π4⇒−cosec2ϕ+sec2ϕ=0⇒−1sin2ϕ+1cos2ϕ=0⇒cos2ϕ−sin2ϕ=0⇒cos2ϕ=0⇒ϕ=π4

again d2sdϕ2=−2cosecϕ×(−cosecϕ.cotϕ)+2secϕ×(secϕ.tanϕ)d2sdϕ2=−2cosecϕ×(−cosecϕ.cotϕ)+2sec⁡ϕ×(sec⁡ϕ.tan⁡ϕ)

at =π4,d2sdϕ2=2cosec2(π4)cot(π4)+2 sec2π4tanπ4=π4,d2sdϕ2=2cosec2(π4)cot⁡(π4)+2 sec2π4tan⁡π4

= 2 × 2 × 1 + 2 × 2 × 1 = 8 > 0

So, minimum value at ϕ=π4ϕ=π4

then S(min)=cotπ4+tanπ4=1+1=2
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