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Vijay Sharma

· started a discussion

· 1 Months ago

74 - 47 = 27....in question it is said to be20

Question:
In a two digit number, the digit at the unit place is 1 less than twice the digit at the ten’s place. If the digit at unit’s and ten’s place are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is – 
Options:
A) 57
B) 24
C) 47
D) 35
Solution:

Ans: (c)

Let ten’s digit = y, then unit digit = 2y – 1

\(\therefore\) original number = 10 y + (2y – 1) = 12y – 1

New number = 10(2y – 1) + y = 21y – 10 

then (21y – 10) – (12y – 1) = 12y – 1 – 20 

y = 4

original number = 12 × 4 – 1 = 47

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Question and answer is right, only there is slight trick in the question.
It says that the difference(i.e 27) is 20 less than the original no which is true as 47-27=20.

Thanks and Regards
Team TR

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