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Sohil Rajput

· started a discussion

· 1 Months ago

wrong (Question: 77300.0 )

x=1 y=1 z=1 satisfy the equation so x+y+z=3

Question:
If \(\cfrac{x^2}{yz} + \cfrac{y^2}{xz}+\cfrac{z^2}{xy}=3\)  , then find the value of \(x+y+z.\)is: 
Options:
A) 100
B) 81
C) 0
D) None of these. 

 

Solution:
  1. If a3 + b3 + c3 – 3abc = 0 then a + b + c = 0

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