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vikas Thakur

· started a discussion

· 1 Months ago

wrong (Question: 352306.0 )

its D

Question:

It was noted that on a section of road, the free speed was 80 kmph and the jam density was 70 vpkm. The maximum flow in vph that could be expected on this road is:

Options:
A)

800

B)

 

1400

C)

 

2800

D)

 

5600

Solution:

Ans:(b)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Given answer is right.

Maximum flow, q(max) = (v*k) / 4
V = free speed
k = jam density

q = 70*80/4
= 1400 vph

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