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Rohan Rocks

· started a discussion

· 1 Months ago

wrong (Question: 233260.0 )

if ( bc is 18 ) then ab = 18^2 - 9^2 = root 243 . now using 1/2 *base * height does not give 40 to be the area .

Question:
Suppose \(\Delta\)ABC be a right-angled triangle where \(\angle \)A = 90o and AD \(\perp \) BC. If \(\triangle\)ABC = 40 cm², \(\triangle\)ACD = 10 cm² and \(\overline{AC}\) = 9 cm, then the length of BC is:  
Options:
A) 12 cm 
B) 18 cm
C) 4 cm
D) 6 cm
Solution:

Ans: (b)

ASHUTOSH SINGH

· commented

· 1 Months ago

Yet to be approved!

Mandapaka Raviteja

· commented

· 1 Months ago

THIS QUESTION WAS CORRECT SOLUTION MUST BE IN ABOVE WAY LIKE ADMIN DID

Harendra upadhyay

· commented

· 1 Months ago

yeah this is a wrong question........and Rohan ur explanation is ryt....
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