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amit pathak

· started a discussion

· 1 Months ago

wrong (Question: 108038.0 )

if we put a=4 then "x" will be 5/8 since it would be equal to 2x

Question:
If 2x = \(\sqrt[]{a}\ + \cfrac{1}{\sqrt[]{a}}\) , a > 0, then the value of \(\cfrac{\sqrt{x^2-1}}{x-\sqrt[]{x^2-1}}\)    is:  
Options:
A) (a – 1) 
B) a + 1
C) \(\cfrac{1}{2}(a + 1)\)
D) \(\cfrac{1}{2}(a - 1)\)
Solution:
Ans: (d)

Putting a = 4, we get : 

x= \(\cfrac{5}{4}\)

Now, 


Now, checking options, option (d) : 

\(\cfrac{1}{2}(a-1)=\cfrac{1}{2}(4-1)=\cfrac{3}{2}\)

Hence, option (d) is the right option.

Vivek

· commented

· 1 Months ago

2x =5/2 and hence x= 5/4
answer is right.
i got the same answer when i put a=9.
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