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nausad alam

· started a discussion

· 1 Months ago

Wrong.. (Question:107577.0)

Wrong explanation....

Question:

In two alloys the ratio of Iron and copper is 4 : 3 and  6 : 1 respectively. If 14 kg of the first alloy and 42 kg of the second alloy are mixed together to form a new alloy, then what will be the ratio of copper to iron in the new alloy:

Options:
A) 11 : 3 
B) 11 : 8
C) 8 : 11
D) None of these
Solution:
Ans: (d)

Hence ratio of copper to iron =\(\cfrac{42 + 42}{56 + 252} \ \ = \cfrac{3}{11}\)

Alternate solution-

proportion of Iron in alloys:


1st alloy 


\(\cfrac{4}{7}\) (total alloy=4=3=7)


2nd alloy


\(\cfrac{6}{7}\) (total alloy= 6+1=7)


Now, according to new data,


1st alloy= 14 kg  = 2nd alloy= 42 kg

= \( \cfrac{4\times 2}{7\times2}\)= \(\cfrac{6\times6 }{7\times6}\)


\(\cfrac{8}{14}=\cfrac{36}{42} \)


So total iron in (14+42) kg ore= 36+ 8= 44 kg

so copper= (14+42)- 44 =12 kg

ratio of copper: iron= 12:44= 3:11

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