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Suraj Kumar

· started a discussion

· 1 Months ago

wrong options (Question: 246548.0 )

i got x=0, root(2), -root(2) as critical point after differentiation
at x=0 min value = -4 nd at x= +-root(2) min value = -1

Question:
Find the minimum value of f(x) = \(x^2+\cfrac{1}{x^2-1}-3\)
Options:
A) 1
B) 0
C) 2
D) 3
Solution:

Ans: (b)


Knowledge Expert

· commented

· 1 Months ago

Dear student
According to solution
if we are put the value of x = root 2
then answer is correct

Best wishes
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