wrong options given (Question: 279591.0 )

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luffy

· started a discussion

· 1 Months ago

wrong options given (Question: 279591.0 )

answer should be
(a2+b2-2)/2
so all options are wrong

Question:

If sin x + sin y = a and cos x + cos y = b, then sin x.sin y + cos x.cos y equal to-

Options:

a² + b² - 2

$(\frac{a^{2} + b^{1} - 2}{2 a b})$

$\frac{a^{2} + b^{1} + 2}{2 a b}$

$\frac{a + b + a b}{a + b - a b}$

Solution:

Ans: (b)

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wrong options given (Question: 279591.0 )

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