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Vivek malik

· started a discussion

· 1 Months ago

as it is given that the fig. is quardilateral and not parallelogram or rhombus which have two equal angles each

Question:
In a quadrilateral ABCD, the line segment bisecting \(\angle \)C and \(\angle \)D meet a E. Then the correct statement is :


Options:
A) \(\angle \)A + \(\angle \)B = \(\angle \)CED 
B) \(\angle \)A + \(\angle \)B = 2 \(\angle \)CED
C) \(\angle \)A + \(\angle \)B = 3 \(\angle \)CED
D) None of the above
Solution:
Ans: (b) 

Nihit

· commented

· 1 Months ago

Yet to be approved!

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