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Anal Penetration

· started a discussion

· 1 Months ago

Wrong interpretation of the question (Question:134195.0)

The question should be read as vertically 'above' to have this solution.

Question:
An aeroplane when flying at a height of 3125 m from the ground passes vertically below another plane at an instant when the angles of elevation of the two planes from the same point on the ground are 30° and 60° respectively. The distance between the two planes at that instant is:
Options:
A) 6520 m 
B) 6000 m
C) 5000 m 
D) 6250 m
Solution:


A and C are  position of planes

BC = 3125 m

AC = x metre

In ∆ABD,

tan 60° = \(\cfrac{AB}{BD}\)

⇒ √3 = \(\cfrac{3125+x}{BD}\)

⇒ BD = \(\cfrac{3125+x}{√3}\)

In ∆BCD,

tan30° = \(\cfrac{BC}{BD}\)

⇒ \(\cfrac{1}{√3 }\) = \(\cfrac{3125}{\cfrac{3125+x}{√3}}\)

⇒ 3(3125)=3125+x

⇒ x = 9375 – 3125

x = 6250 metre


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