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Ashutosh Kumar

· started a discussion

· 1 Months ago

Wrong explanation- Put X=0 (Question: 246548.0 )

On putting X=0, the value comes out to be -3, which is definitely less than 0.

Question:
Find the minimum value of f(x) = \(x^2+\cfrac{1}{x^2-1}-3\)
Options:
A) 1
B) 0
C) 2
D) 3
Solution:

Ans: (b)


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