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Sagar Gaikwad

· started a discussion

· 1 Months ago

Please give question and their verified ans

Question:
Find the remainder when the product of 10 consecutive natural numbers starting from 8641 is divided by 8640.
Options:
A) 3
B) 8639
C) 0
D) 55
Solution:

Ans: (c)

Required Remainder 


Rahul Verma

· commented

· 1 Months ago

4*5*6*8*9=8640
==> numerator is completely divisible by 8640
==Re=0

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