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Sandeep

· started a discussion

· 1 Months ago

wrong calculation also (Question: 108726.0 )

height of the pyramid is wrongly calculated. Base is not a it is .863a

Question:

A pyramid is such as its base is a regular hexagon of side a cm. If the slant height of the pyramid is \(\cfrac{5a}{2}\) cm, then what will be the volume of the pyramid?

Options:
A) 3a2 cm3
B) 3\(\sqrt[]{2}\)a3 cm3
C) 6a3 cm3
D) None of these 
Solution:
Ans: (d) Area of base 

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

It is clearly given in question base is a regular hexagon of side 'a' cm and slant height of the pyramid is 5a/2 cm,
Volume of pyramid = 1/3×Area of base×height
Base is hexagon thus area of hexagon= 3 root3/2 * side^2.
Height- It is calculated by applying pythagoras if apothem(slant height) and base are known. through all the given formulas try to solve again.

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