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suru yadavarao

· started a discussion

· 1 Months ago

wrong answer (Question:429286.0)

option is wrong

Question:

For steady flow through an insulated horizontal constant diameter pipe, this

property remains constant:

Options:
A) Enthalpy 
B) Internal energy
C) Entropy
D) Volume
Solution:

Applying steady flow energy equation

\(q+h_1+\cfrac{V^2_1}{2} + Z_1g = h_2 + \cfrac{V^2_2}{2} + Z_2g + \omega\)

Insulated

∴ g = 0

No work interaction

∴ \(\omega = 0\)

Horizontal pipe

∴ Z1 = Z2

Since constant diameter

∴ at any section (i) and (ii)

\(A_1V_1\rho_1 = A_2V_2\rho_2\)

⇒ \(V_1\rho_1 = V_2\rho_2\) (∴ A1= A2)

Since any thing is not mentioned about compressibility, taking the fluid as incompressible.

∴ V1 = V2

∴ SFEE reduces to

h1 = h2

⇒ Enthalpy is constant.

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