wrong answer, (Question: 368377.0 )

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unkown

· started a discussion

· 1 Months ago

wrong answer, (Question: 368377.0 )

on substituting a=b=-1 and c=1 we get 3

Question:

If a, b, c are positive integer, then minimum value of $\frac{(a^{2} + a + 1) (b^{2} + b + 1) (c^{2} + c + 1)}{a b c}$

Options:

Solution:

Ans:(c) a, b, c are positive integer (given).

To find the minimum value of $\frac{(a^{2} + a + 1) (b^{2} + b + 1) (c^{2} + c + 1)}{a b c}$

Let, a = b = c = 1.

We cannot take a = 0, or b = 0 or c = 0 as denominator cannot be 0, it will give infinity as solution.

So, taking a = b = c = 1.

We get, $\frac{(1 + 1 + 1) (1 + 1 + 1) (1 + 1 + 1)}{1 \times 1 \times 1}$ ⇒ 3 × 3 × 3 = 27

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct
In the Question, It is specified that a,b,c are positive integers.

Best wishes
Team TR

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wrong answer, (Question: 368377.0 )

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