Wrong answer (Question: 368377.0 )

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ravi jepaal

· started a discussion

· 1 Months ago

Wrong answer (Question: 368377.0 )

take a=b=c=-1 and answer is -1.

Question:

If a, b, c are positive integer, then minimum value of $\frac{(a^{2} + a + 1) (b^{2} + b + 1) (c^{2} + c + 1)}{a b c}$

Options:

Solution:

Ans:(c) a, b, c are positive integer (given).

To find the minimum value of $\frac{(a^{2} + a + 1) (b^{2} + b + 1) (c^{2} + c + 1)}{a b c}$

Let, a = b = c = 1.

We cannot take a = 0, or b = 0 or c = 0 as denominator cannot be 0, it will give infinity as solution.

So, taking a = b = c = 1.

We get, $\frac{(1 + 1 + 1) (1 + 1 + 1) (1 + 1 + 1)}{1 \times 1 \times 1}$ ⇒ 3 × 3 × 3 = 27

vaishali

· commented

· 1 Months ago

in the question a condition is given that a,b,c are positive integers hence -1 is not possible

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
In the question it is specified that a,b,c are positive integers.

Thanks and regards
Team TR

ravi jepaal

· commented

· 1 Months ago

sorry values can't be negative.

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Wrong answer (Question: 368377.0 )

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