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Aravind

· started a discussion

· 1 Months ago

wrong answer (Question: 368302.0 )

S1/S2 = root of (T2/T1)

80/S2 = root of (24/5*3/10)

80*5/6 = S2

66(2/3)

Question:

Two trains start running in opposite direction from two places and reach the destination mid-point after 3 13    hours and 4 45    hours. If the speed of the first train is 80 km/hr, then what is the speed of the 2nd train (in km/hr)?

Options:
A)

64 23   

B)

66 23   

C)

55 59   

D)

75

Solution:

Ans:(c) 

  

sandeep kumar tiwari

· commented

· 1 Months ago

you are correct but i would like to say that this is different from that question what you think in this questtion it has been given that when both reach mid point of distance not the time after meeting each other so carefully read and understand the sense

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct
Please read the Question carefully
Alternate solution
T1 = 10/3 , T2 = 24/5
we know the speed is inversly praportional to time
so, S1 = 3/10 , S2 = 5/24
given S1 = 80
compare the speed
x * 3/10 = 80
x = 800/3
Req. answer is = 800/3 x 5/24
= 500/9

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