wrong answer (Question:366024.0)

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gireesh kumar

· started a discussion

· 1 Months ago

wrong answer (Question:366024.0)

check once

Question:

D and E are points on side AB and AC of ΔABC. DE is parallel to BC. If AD:DB = 2:5 and area of ΔADE is 8 sq cm, what is the ratio of area of ΔADE and area of quadrilateral BDEC?

Options:

4:45

45:4

8:45

45:8

Solution:

$\begin{matrix} \frac{A D}{D B} = \frac{2}{5} \\ ∴ \frac{A D}{A B} = \frac{2}{2 + 5} = \frac{2}{7} \\ S i n c e D E | | B C, \\ Δ A D E ~ Δ A B C (B y A A S i m i l a r i t y) \\ ∴ \frac{A r e a o f Δ A D E}{A r e a o f Δ A B C} = (\frac{A D}{A B}) = {(\frac{2}{7})}^{2} \\ = > ∴ A r e a o f Δ A B C = 8 \times {(\frac{7}{2})}^{2} = 98 c m^{2} \end{matrix}$

$∴$ Area of quadrilateral BDEC = Area of ∆ABC – Area of ∆ADE = 98-8=90cm²

$∴ \frac{A r e a o f Δ A D E}{A r e a o f q u a d r i l a t e r a l B D E C} = \frac{8}{90} = \frac{4}{45}$

gireesh kumar

· commented

· 1 Months ago

sorry.. answer is correct

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wrong answer (Question:366024.0)

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