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REDDI.PRADEEP

· started a discussion

· 1 Months ago

Option A is correct

Question:

An ac meter of resistance Rm and reactance Xm is connected in series with a resistance Rs. A shunt of impedance (Rsh + jXsh) is applied in parallel to the existing combination of meter and R s. The current division across the two branches will be independent of frequency when 

  

Options:
A)

  

B)

  

C)

  

D)

  

Solution:

Ans:(d) Current is same in both branch when impedance in both branch are same

  

amar bajpai

· commented

· 1 Months ago

yes bro time constant play an important role to make the branches independent from frequency... so option A is correct

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