wrong answer (Question:325755.0)

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Pravesh Vats

· started a discussion

· 1 Months ago

wrong answer (Question:325755.0)

after putting a=45 the answer will 0

Question:

The value of $(2 c o s^{2} A - 1) (\frac{1 + t a n A}{1 - t a n A} + \frac{1 - t a n A}{1 + t a n A})$ is:

Options:

Solution:

$\begin{matrix} (2 c o s^{2} A - 1) (\frac{1 + t a n A}{1 - t a n A} + \frac{1 - t a n A}{1 + t a n A}) = (2 c o s^{2} A - 1) (\frac{s e c^{2} A}{\frac{c o s^{2} A - s i n^{2} A}{c o s^{2} A}}) \\ = (2 c o s^{2} A - 1) 2 (\frac{1}{2 c o s^{2} A - 1}) = 2 \end{matrix}$ Note: $[1+tan^2A= sec^2A] $ and $ tanA=\frac{sinA}{cosA}$

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wrong answer (Question:325755.0)

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