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Anil

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· 1 Months ago

y*162=y*2*3^4

For least value, Y=32= 2^5.
y*162= 2^5*2*3^4=2^6*3^4=8^2*9^2

Question:

Find the smallest number y such that y × 162 is a perfect cube.

Options:
A)

24

B)

27

C)

32

D)

36

Solution:

Ans: (d)

y × 162 = perfect cube

y × 3 × 2 × 27 = perfect cube

For perfect cube y = 36

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