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kundan

· started a discussion

· 1 Months ago

r/n is correct answer

Question:
A wire of resistance R is cut into 'n' equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be –
Options:
A) nR
B) \(\cfrac{R}{n}\)
C) \(\cfrac{n}{R}\)
D) \(\cfrac{R}{n^2}\)
Solution:

Ans:(d) 

Since R is directly proportional to length of the wire, when wire is cut into equal parts, then Resistance of each part = \(\cfrac{R}{n}\)

When the wires are connected in parallel, then the equivalent resistance of combination is –

1/R2 = n/R  +  n/R + ... (n terms)

       = n. n/R

       = n^2/R

R2 = R/n^2.

Gaurav Saini

· commented

· 1 Months ago

correct ans is D

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Since R is directly proportional to length of the wire, when wire is cut into equal parts, then Resistance of each part = R/n
When the wires are connected in parallel, then the equivalent resistance of combination is –
1/R2 = n/R + n/R + ... (n terms)
= n. n/R
= n^2/R
R2 = R/n^2.

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