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Sashikanta Sunani

· started a discussion

· 1 Months ago

wrong answer (Question:140751.0)

How can 3000/500 will be 5?

Question:

From a point charge, there is a fixed point A. At A, there is an electric field of 500 V/m and potential distance of 3000 V. Distance between point charge and A is

Options:
A) 12 m
B) 6 m
C) 16 m
D) 29 m
Solution:
Ans: (b) 

E=\(\cfrac{V}{d}\)OR d=\(\cfrac{V}{E}\)= \(\cfrac{3000}{500}\)= 6m

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Your issue has been solved , please reattempt the question.
Keep learning,
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