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Sai Kumar U

· started a discussion

· 1 Months ago

wrong answer (Question: 117234.0 )

when the inner square side becomes a/root2 then the radius of inner circle becomes a/2root2 then the area becomes 3*root3asquare/32

Question:
What is the area of the inner equilateral triangle if the side of the outermost square is ‘a’? (ABCD is a square).

Options:
A) \(\cfrac{3\sqrt[]{3}a^2}{32}\)
B) \(\cfrac{\sqrt[]{3}a^2}{16}\)
C) \(\cfrac{5\sqrt[]{3}a^2}{32}\)
D) \(\cfrac{5\sqrt[]{3}a^2}{64}\)
Solution:
Ans: (b) \(BD=a,EF=\cfrac{a}{2}\)

\(\therefore\) area of equilateral triangle EFG \(=\cfrac{\sqrt[]{3}}{4}\left ( \cfrac {a}{2} \right )^2=\cfrac{\sqrt[]{3}a^2}{16}\)

Knowledge Expert

· commented

· 1 Months ago

the side of the outermost square is ‘a’.......not of ABCD....Please read the question very carefully....
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