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ankur

· started a discussion

· 1 Months ago

wrong answer (Question: 112237.0 )

answer is 3000. we have to find the amount lent to B not A

Question:
I had \(\unicode{x20B9} \)10,000 with me. Out of this money I lent some money to A for 2 years at 15% simple interest. I lent the remaining money to B for an equal number of years at 18% simple interest. After 2 years, I found that A had given me \(\unicode{x20B9} \)360 more as interest as compared to B. The  amount of money which I had lent to B must have been:
Options:
A) \(\unicode{x20B9} \)2,000
B) \(\unicode{x20B9} \)3,000
C) \(\unicode{x20B9} \)4,000
D) \(\unicode{x20B9} \)5,000
Solution:
Ans: (c)

Suppose money lent to A = \(\unicode{x20B9} \)x

\(\therefore\) Money lent to B = \(\unicode{x20B9} \)(10,000-x)

Interest given by A, in 2 years at 15% 

= \(\unicode{x20B9}\cfrac{x\times2\times15}{100} \)

Interest given by B, in 2 years at 18% 

= \(\unicode{x20B9}\cfrac{(10,000-x)\times2\times18}{100} \)

= \(\cfrac{x\times2\times15}{100} \)    - \(\cfrac{(10,000-x)\times2\times18}{100} \)       =360

5x - 60,000 + 6x = 60 00

or 11x = 66,000

\(\therefore\) x = 6000

Hence amount lent to B = \(\unicode{x20B9} \)4,000

Avnish Kaushal

· commented

· 1 Months ago

hutiye..

ankur

· commented

· 1 Months ago

kkk i was wrong
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