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Lokesh Bhandari

· started a discussion

· 1 Months ago

Wrong answer (Question:111097.0)

Please check your solution.. there's an extra a^2

ankur

· started a discussion

· 1 Months ago

wrong answer (Question: 111097.0 )

answer should be d as the coordinates of the centre are (a/2,a/2).

This topic is not avialable

UJJAWAL

· started a discussion

· 1 Months ago

Wrong answer !! (Question: 111097.0 )

Wrong explanation .

Question:
ABCD is a square whose side is a. If AB and AD be the co-ordinate axes, then the equation of the circumcircle is:
Options:
A) x2+y2+2a(x+y)=0
B) x2 + y2 + a (x+y) =0
C) x2+y2 - a (x+y)  = 0
D) x2+y2 - a (x - y) = 0
Solution:
Ans: (c)


Let the side be 'a'

It start from origin A (0, 0)

B = Y axis = (0, a)

D = X axis = (a, 0)

C = (a, a)

Since AC is diameter

We will use the diametric form of circle

(x – x1) (x – x2) + (y – y1) (y – y2) = 0

(x – 0) (x – a) + (y – 0) (y – a) = 0

x (x – a) + y (y – a) = 0

x2 – ax + y2 – ay = 0

x2 + y2 – a (x + y) = 0

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