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SHASHI KUMAR

· started a discussion

· 1 Months ago

wrong answer (Question: 111047.0 )

where is the area of the floor in given solution because total area is 1100
pls remove confusion.

Question:
The cross-section of a railway tunnel is a rectangle 6m broad and 8m high, surounded by a semi-circle as shown in the adjoining figure. The tunnel is 35 m long. The cost of plastering the internal surface of the tunnel excluding the floor, at the rate of \(\unicode{x20B9} \)3 per m2 is :


Options:
A) \(\unicode{x20B9} \)2380
B) \(\unicode{x20B9} \)1780
C) \(\unicode{x20B9} \)2170
D) \(\unicode{x20B9} \)2670
Solution:
Ans: (d) (Area of parallel walls of height 8 m) + (Area of semi cylinderical top)

\(\therefore\) Area of wall \(=2\times(8\times35)=560m^2\)

\(\therefore\) Area of semi-cylinderical top = \(\frac{2\pi rh}{2}\)

\(=\cfrac{22}{7}\times3\times35=22\times3\times5=330\ m^2\)

\(\therefore\) Total area to be plastering \(=560+330=890m^2\)

\(\therefore\) Cost of plastering \(=\unicode{x20B9}(890\times3)=\unicode{x20B9}2670 \)

Vishal

· commented

· 1 Months ago

Yes you are right.....

Dipti Sharma

· commented

· 1 Months ago

please read the english version of this q.. there is given that area of floor is excluded..
so now we have to solve the q. in hindi then if we couldn't get the ans. we have to saolve this in english...hahahahah....jai ho paramount

murari krishan

· commented

· 1 Months ago

u r wright brother
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