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Jaydip Akbari

· started a discussion

· 1 Months ago

wrong answar (Question: 331922.0 )

corect is 4

Question:

The polar moment of inertia of a hollow shaft of outer diameter (D) and inner diameter (d) is

Options:
A)

p16    (D3 -  d3)

B)

p16    (D4 -  d4)

C)

p32    (D4 -  d4)

D)

p64    (D4 -  d4)

Solution:

Ans: (c)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
The given option is correct.

For a hollow shaft, J =∏∗[D4−d4]/32 where ‘D’ is the outer diameter of the shaft and ’d’ is the inner diameter
of the shaft.

Thanks and Regards
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