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AMAN KUMAR

· started a discussion

· 1 Months ago

wr (Question:32349.0)

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Question:
If cos \(\theta\) = \(\cfrac{2t}{1+t^2}\)  find the value of tan \(\theta\).
Options:
A) \(\cfrac{1+t^2}{2t}\)
B) \(\cfrac{2t-1}{t^2}\)
C) \(\cfrac{1-t^2}{2t}\)
D) \(\cfrac{1-2t}{t^2}\)
Solution:

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