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Vandana K

· started a discussion

· 1 Months ago

Please explain why you have used variable 'x' when you can put 10 at its place. I am getting 30 kg as answer.

Question:

A shopkeeper mixed 45 kg rice of cost Rs.10 per kg and some amount of other type of rice of cost Rs.15 per kg and sold the mixture at Rs.14 per kg. Thus, if he gained 5%, then the amount of other type of rice was:

Options:
A) 90 kg.
B) 15 kg.
C) 20 kg.
D) 30 kg.
Solution:
Ans: (a) Selling price of mixture = \(\unicode{x20B9} \) 14

Cost price of mixture = \(\unicode{x20B9}\cfrac{14}{1.05}\unicode{x20B9} = \cfrac{40}{3} \)

Let the amount of rice costing \(\unicode{x20B9} \)15 per kg = x kg

Rice 1                           Rice2

10                                 15

                 

                  40/3


15-40/3 =5/3              40/3-10 = 10/3


Quantity of First variety of Rice = 5/3 = 45

                                               1 = 45x3/5 = 27

therefore, quantity of second variety of Rice = 27x10/3 = 90kg

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Please read the solution properly.
Keep learning,
Team TR

Content Admin Review

· commented

· 1 Months ago

Yet to be approved!

Saurabh Chauhan

· commented

· 1 Months ago

use of allegation method in given solution is wrong.....we will put 10 at place of x, then we use A.M. , we will get the ratio of mixing rice is 1:2....so 1 represents 45 kg, then 2 will represent 90 kg.. so ans is 90

Ashwani Tiwari

· commented

· 1 Months ago

Yes artery is right

Arti

· commented

· 1 Months ago

go through options

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