why not option C (Question: 277481.0 )

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Ambarish Gupta

· started a discussion

· 1 Months ago

why not option C (Question: 277481.0 )

since both angle B and Q are cyclic so sum would be 180 degree....so c=(180-b)/2=90-angle ABC/2

Question:

ABC is triangle is which AB = AC and P is a point on side AC. A line is drawn from point C in such a way that it intersects which produced BP at Q and $∠$ ABQ = $∠$ ACQ what is $∠$ AQC?

Options:

$90^{o} - \frac{1}{2} ∠ B A C$

$90^{o} + \frac{1}{2} ∠ A C B$

$90^{o} - \frac{1}{2} ∠ A B C$

$90^{o} + \frac{1}{2} ∠ B A C$

Solution:

Ans: (d)

Ambarish Gupta

· commented

· 1 Months ago

angles*

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why not option C (Question: 277481.0 )

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