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Ankit

· started a discussion

· 1 Months ago

Why can't we take value of a=1 (Question: 108038.0 )

Why can't we take value of a=1
That leads to C as correct answer
Is there something wrong with question

Question:
If 2x = \(\sqrt[]{a}\ + \cfrac{1}{\sqrt[]{a}}\) , a > 0, then the value of \(\cfrac{\sqrt{x^2-1}}{x-\sqrt[]{x^2-1}}\)    is:  
Options:
A) (a – 1) 
B) a + 1
C) \(\cfrac{1}{2}(a + 1)\)
D) \(\cfrac{1}{2}(a - 1)\)
Solution:
Ans: (d)

Putting a = 4, we get : 

x= \(\cfrac{5}{4}\)

Now, 


Now, checking options, option (d) : 

\(\cfrac{1}{2}(a-1)=\cfrac{1}{2}(4-1)=\cfrac{3}{2}\)

Hence, option (d) is the right option.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
When you take a= 1 then x will also become 1
On putting x=1 , you get answer =0
Then also the option D is correct and will give you 0 as the answer.
The given answer is correct.

Thanks and Regards
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