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Ashish Singla

· started a discussion

· 1 Months ago

why 15 subtracted? (Question: 32626.0 )

exp?

Question:
The least fraction to be subtracted from the expression \(\cfrac{3\cfrac{1}{4}-\cfrac{4}{5}\times \cfrac{5}{6}}{4\cfrac{1}{3}\div\cfrac{1}{5}-(\cfrac{3}{10}+21\cfrac{1}{5})}\)      to make it an integer
Options:
A) \(\cfrac{1}{2}\)
B) \(\cfrac{5}{6}\)
C) \(\cfrac{1}{4}\)
D) \(\cfrac{3}{10}\)
Solution:


 \(\cfrac{3\cfrac{1}{4}-\cfrac{4}{5}of \cfrac{5}{6}}{4\cfrac{1}{3}\div\cfrac{1}{5}-(\cfrac{3}{10}+21\cfrac{1}{5})}\)


Required answer = \(15\cfrac{1}{2}-15=\cfrac{1}{2}\)

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