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Chakradhar

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· 1 Months ago

7sin2θ+3cos2θ=4 3sin2θ+3cos2θ+4sin2θ=4 ⇒3(sin2θ+cos2θ)+(4sin2θ)=4 ⇒4-3=4sin2θ ⇒(sinθ=1/√2)....... so teta=45....

Question:

 If  7sin2θ+3cos2θ=4    then value of  cosθ0<θ<900    is

Options:
A)

  62   

B)

  32   

C)

  22   

D)

  52   

Solution:

7sin2θ+3cos2θ=43sin2θ+3cos2θ+4sin2θ=43(sin2θ+cos2θ)=4(1-sin2θ)34=cos2θcosθ=32   

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